A building 62 feet tall casts a shadow 21 meters long . At what angl is the sun shining on the building

71.3°

Step-by-step explanation:

A building 62 feet tall casts a shadow 21 meters long . At what angle is the sun shining on the building?

We solve this question using the Trigonometric function of Tangent

tan x = Opposite/Adjacent

Where

Opposite = 62ft

Adjacent = 21 ft

x = Angle

Hence,

tan x = 62/21

x = arc tan (62/21)

x = 71.288262125°

Approximately = 71.3°

step by step solution :

step   1   :

1.1     4 = 22

(4)3 = (22)3 = 26

equation at the end of step   1   :

  ((23) • 26)2

step   2   :

equation at the end of step   2   :

  (23 • 26)2

step   3   :

final result :

  218

ya

"standard form:

3x2 + 14x − 10 = 0

solutions based on quadratic formula:

x1   = −14 − √ 142 − 4×3×(−10) /   2×3   = −14 − 2 × √ 79 /   6   ≈ −5.296

x2   = −14 + √ 142 − 4×3×(−10) /   2×3   = −14 + 2 × √ 79 /   6   ≈ 0.629