Prove that
cos 9°+sin 9°/cos9°-sin9° =cot 36°
plzz fass i need to writw this​

Step-by-step explanation:

LHS = (Cos9° + Sin9°) / (Cos9° - Sin9°)  

Divide by Numerator  and Denominator   by  Cos9°  

LHS = (1 + Tan9°) / (1 - Tan9°)

       = (Tan 45° + Tan 9°) / (1 - Tan 45° * Tan 9°)  

       = Tan (45°+9°)  

       = Tan 54°

       = Cot 36°

hope it helps :)

the image of (6, 9) under a dilation is (4, 6). the scale factor is

85.560%

step-by-step explanation:

conditional probability is defined as:

p(a|b) = p(a∩b) / p(b)

in other words, the probability that a occurs, given that b has occurred = the probability that both a and b occur / the probability that b occurs.

in this example:

p(turns 64 | turns 44) = p(turns 64 & turns 44) / p(turns 44).

if someone turns 64, they must have already turned 44, so:

p(turns 64 | turns 44) = p(turns 64) / p(turns 44)

on page 42, we see that of the original 100,000, 94944 turn 44, and 81234 turn 64.   therefore:

p(turns 64 | turns 44) = 81234 / 94944

p(turns 64 | turns 44) = 0.85560