Example 1 (a) Consider the pulse rates of two patients in a hospital for ten different days:
Patient A: 17 16 70 69 70
75 78 70 71
69
Patient B: 59
92
60
80 71
65
50
88
95 70
Find the mean pulse rate for each patient and the corresponding range.
​

1a. Mean pulse rate for A = 60.5

1b. Range for A = 62

2a. Mean pulse rate for B = 73

2b. Range for B = 45

Step-by-step explanation:

1a. Determination of the mean pulse for patient A.

Data => 17, 16, 70, 69, 70, 75, 78, 70, 71, 69

Mean =?

The mean pulse rate for patient A can be obtained as follow:

Summation of data = 17 + 16 + 70 + 69 + 70 + 75 + 78 + 70 + 71 + 69

Summation of data = 605

Number of data = 10

Mean = summation of data / number of data

Mean = 605 / 10

Mean pulse rate for A = 60.5

1b. Determination of the range for patient A

Data => 17, 16, 70, 69, 70, 75, 78, 70, 71, 69

Range =?

Range = Highest – Lowest

Highest = 78

Lowest = 16

Range = Highest – Lowest

Range = 78 – 16

Range for A = 62

2a. Determination of the mean pulse for patient A.

Data => 59, 92, 60, 80, 71, 65, 50, 88, 95, 70

Mean =?

The mean pulse rate for patient B can be obtained as follow:

Summation of data = 59 + 92 + 60 + 80 + 71 + 65 + 50 + 88 + 95 + 70

Summation of data = 730

Number of data = 10

Mean = summation of data / number of data

Mean = 730 / 10

Mean pulse rate for B = 73

2b. Determination of the mean pulse for patient B.

Data => 59, 92, 60, 80, 71, 65, 50, 88, 95, 70

Range =?

Range = Highest – Lowest

Highest = 95

Lowest = 50

Range = Highest – Lowest

Range = 95 – 50

Range for B = 45

30 miles

step-by-step explanation:

we know that 60 seconds equals 1 minute and 60 minutes 1 hour

44 ft       60 sec     60 min     158400   ft

  *   *   =

1 sec       1 min       1 hour         hour

we know that there are 5280 ft per mile

158400   ft       1 mile         30 miles

  *   =

1   hour               5280 ft     1 hour

so in 1 hour   it can travel 30 miles

answer:

step-by-step explanation: