A rectangular block of ice measures 42 cm × 25 cm × 18 cm. Calculate its total surface area and weight in kilogram if 1 cm3 of ice weighs 0.9 grams.

T.S.A = 4512cm^2

volume = 18900cm^3

weight = 17.01 kg

Step-by-step explanation:

T.S.A of cuboid = 2(lb+bh+lh)

= 2(42x25 + 25x18 + 42x18)

=2(1050 + 450 + 756)

=2 x 2256

= 4512cm^2

to find weight, we've to find the volume of the ice cube

therefore, volume of a cuboid = lbh

=42 x 25 x 28

=18900cm^3

weight of 1cm^3 of ice = 0.9grams

therefore weight of 18900cm^3 of ice = 18900 x 0.9

= 17010 grams = 17.01kg

Hope it helped u,

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answer: my brother can figure it out, imma go get him so i can answer : ) edit: my brother is sleeping, sorry man

step-by-step explanation: