5 men or 7 women or 9 girls can do a piece of work in 15 days. How many days will 1 men 1 women and 1 girl take to do the same
work?
In cummor camn food was available for 120 children at the rate of​

Step-by-step explanation:

5 men × 15 days = 75 man-days

Each man does 1/75 of the job per day

7 women × 15 days = 105 woman-days

Each woman does 1/105 of the job per day.

9 girls × 15 days = 135 girl-days

Each girl does 1/135 of the job per day.

Least common multiple of 75, 105, and 135 =

Working together, 1 man, 1 woman, and 1 girl do 1/75 + 1/105 + 1/135 = 143/4725 of the job per day, finishing in 4725/143 = 33.04 days

answer: the correct answer is -32

step-by-step explanation:

the value of x is 9 ⇒ answer b

step-by-step explanation:

* we can solve this problem using cosine and sine rule

- in δ abc

∵ ab = 36 , bc = 28 , ac = 16

- lets find the measure of angle b using the cosine rule

∵ cos b = [ab² + bc² - ac²]/2(ab)(bc)

∴ cos b = [36² + 28² - 16²]/2(36)(28)

∴ cos b = 19/21

∴ m∠b = cos^-1(19/21) ≅ 25°

- lets find the measure of angle a using the sine rule

∵ sina/bc = sinb/ac = sinc/ab

∴ sina/28 = sin25°/16 ⇒ by using cross multiplication

∴ sina = 28 × sin25°/16

∴ sina = 0.7396

∴ m∠a = sin^-1(0.7396) ≅ 48°

- from the figure m∠abd = m∠dbc

∵ m∠abc = 25°

∴ m∠abd = 25°/2 = 12.5°

- in δabd

∵ m∠a = 48° , m∠abd = 12.5°

∵ the sum of the measures of the interior angles of any δ is 180°

∴ m∠adb = 180° - (48° + 12.5°) = 119.5°

∵ ab = 36

∵ ad = x

- use the sine rule to find x

∵ sin∠adb/ab = sin∠abd/x

∴ sin119.5°/36 = sin12.5°/x ⇒ by using cross multiplication

∴ x = 36 × sin12.5°/sin119.5° = 8.95 ≅ 9

* the value of x is 9