Can anyone help me to solve this question
​

angle x = 57.5°

Step-by-step explanation:

Let say Base of triangle = 2RThen Radius of circle = RArea of Semi Circle = (1/2) π R²Let say Perpendicular height of isosceled triangle = hthen area of triangle = (1/2) * 2R * h= R * hR * h =  (1/2) π R²=> h = π R/2Tan x  =   h/R=> Tanx  =  π R/2R=> Tanx  =  π/2=> Tanx = 3.14/2=> Tanx = 1.57=> x = Tan⁻¹(1.57)=> x = 57.5°

Angle x = 57.5°