I need help using the Expand Group and Factoring method on this problem.

27a^2+72a+28

1 x (27a^2+72a+28)  or 1(27a^2+72a+28)

Step-by-step explanation:

First find the GCF (greatest common factor) of 27a squared 72a and 28. It is 1 because there is nothing else that can go in.

So put 1 outside the parentheses and keep the terms

1 x (27a^2+72a+28)

equal to

step-by-step explanation:

-22

times both sides by 2, times () by 8, add alile terms, move terms, add alike and caculate divide both sides by 3