The ideal gas law states that the volume, v, of a gas in liters varies directly with the amount of the gas in moles, n, and the absolute temperature, T, in kelvins and varies inversely with the pressure, P, in atmospheres. Two moles of a gas have a volume of 35.424 L at 270 kelvins when P = 1.25 atmospheres. What is the volume of 3 moles of a gas at 280 kelvins when P = 1.5 atmospheres? 11.48 L 27.33 L 45.92 L 103.32 L

45.92 L

Step-by-step explanation:

A & B are directly proportional (vary directly) if A = k * B, where k is some constant, called the 'constant of proportionality'.

A & B are inverselyproportional (vary inversely) if A = k/B, where k is some constant,  called the 'constant of proportionality'.

So here, in math terms, we are told that  V = (r * n * T)/P,  where 'r' is the constant of proportionality.

We are also told that                            35.424 = (r * 2  *270)/1.25

We can solve for the constant, r.

r = PV/nT = (1.25 * 35.424)/(2 * 270) = 44.28/540 = 0.082

r = 0.082

In the second scenario, n =3, T = 280, P =1.5, r always equals 0.082, and we are asked to find V, the volume.

V = nrT/P

V = (3)(0.082)(280)/1.5 = 68.88/1.5 = 45.92, in liters

answer: the answer is simply nothing.

step-by-step explanation: because there is no ending to this question

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