Relations mapping domain values to range values can be described as one-to-one or not one-to-one. a. If one x-value maps to many y-values (one-to-many), does the relation represent a function? If the x-and y-values are reversed, does the relation represent function? Explain.

b. If the relation is not one-to-one, does the relation represent a function? If the x- and y-values are reversed, does the relation represent a function? Explain.

c. If the relation is one-to-one, does the relation represent a function? If the x-and y-values are reversed, does the relation represent a function? Explain.

a. In a one-to-many relation, at least one _ value maps to _ _ value. This means a one-to-many relation _ be a function ​

a. In a one-to-many relation, at least one (input) value maps to (more than one) (output) value. This means a one-to-many relation (cannot) be a function,

Step-by-step explanation:

a. she will receive a refund of $278.

step-by-step explanation:

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?