The distance covered by a cyclist in 2 hours is 4 km less than the distance covered by a pedestrian in 6 hours. Find the speed of the cyclist if it is known that it is 10 km / h more than the speed of a pedestrian.

Step-by-step explanation:

2c=6p-4 and c=p+10 so p=c-10 then 2c=6p-4 becomes

2c=6(c-10)-4

2c=6c-60-4

2c=6c-64

-4c=-64

c=16

So the cyclist is traveling at 16 km/hr

16 km/hr

Step-by-step explanation:

P = distance covered by the pedestrian in 6 hours in km

C = distance covered by the cyclist in 2 hours in km= P - 4

Vp = speed of the pedestrian in km/hr

Vc = speed of the cyclist in km/hr = Vp + 10

The cyclist had a constant speed for 2 hours which covered a distance of C or  (P-4).

2(Vc) = C = P - 4

The pedestrian had a constant speed for 6 hours which covered a distance of P

P = 6(Vp)

Since you know what P and Vc are in terms of Vp, rewrite the equation 2(Vc) = C = P - 4 in terms of Vp.

2(Vc) = C = P - 4 becomes

2(Vp + 10) = 6(Vp) - 4

Solve for Vp:

2(Vp + 10) = 6(Vp) - 4

2(Vp) + 20 = 6(Vp) - 4

4(Vp) = 24 ==> Vp = 6

You have the speed of the pedestrian, and with it you can solve the speed of the cyclist.

Vc = Vp + 10 = 6 + 10 = 16 km/hr

x=6 and x=3

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