find the equation for the line passes through the point(5,2) and that is perpendicular to the line with the equation y=2/3×-3​

hi

Step-by-step explanation:

Answer

The equation of line joining the points (2,3) and (3,−1) is  

3+1

y+1

​  

=  

2−3

x−3

​  

or, y+1=−4x+12

or, y+4x=11(1)

Now the equation of line perpendicular to the line (1) is 4x−y=c(2) { Where c is constant].

Given the equation (2) passing through (5,2) then we get, c=18.

So the equation of the line is 4x−y=18.