9. A ship sails 20km due North. It changes direction and then sails 15km due East.
How far is it from its starting point?

Ans = appx 10.439 units

Step-by-step explanation:

This answer will vary depending on the starting latitude of the ship due to earth not being flat, despite suddenly popular opinions.

So if we used a flat cartesian space ignoring the curvature of the earth we could have a fixed constant answer to this question. Lets do it that way.

Just to clarify: NO the earth is not flat.

Another assumption of this question is the difference between compass north and true north, which we have to throw out for the same reasons.

Real world answers to this question would not be as simple… #imjustsaying

Ok so first travel northeast, lets call that a bearing of 45 degrees directly northeast to also squash any variations there… then a bearing of 250 degrees which ill assume is not a relative bearing (LOTS OF ASSUMPTIONS GOING ON HERE) which is sortof in the west-southwest direction.

The angle at the turn goes from 45 to 250. reversing the 45 shows our angle to be between 250 and 180+45=225 so the angle is 25 degrees with one leg being 20 units (kilometers) long and the other leg being 12 units long. How many units apart are the two points that are connected to that angle?

(12sin(25))^2+(20–12cos(25))^2 = x^2

Enjoy calculating. Make sure that 25 is in degrees and not in radians.

Ans = appx 10.439 units

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step-by-step explanation:

what is the question?

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