HELP! Write two mixed numbers so that all rules are applied:
1. One number is larger than the other by 4 2/3
2. The difference of the numbers is equal to the smaller number.
3. The sum of the numbers is natural number

Step-by-step explanation:

“One number is larger than the other by 4 2/3”

x = y + 4⅔

“The difference of the numbers is equal to the smaller number.”

x-y = y

x = 2y

y + 4⅔ = 2y

y = 4⅔

x = 2y = 9⅓

“The sum of the numbers is natural number”

x+y ∈ ℕ

9⅓ + 4⅔ = 14 ∈ ℕ

9 1/3 and 4 2/3

Step-by-step explanation:

:)

so far i think you have the right thing going for you just remember soh cah toh

step-by-step explanation:

sine over hypotenuse

cosine   equals adjacent

tangent over hypotenuse

19479 is the answer ^^