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T
The perimeter of a rectangular garden is 68 yards. The width of the garden is five yards less than twice the length.
(a) Find the length and width of the garden.
(b) What is the area of the garden?
The length of the garden is
(Type an integer or a decimal.)
The width of the garden is
V (Type an integer or a decimal.)
The area of the garden is
(Type an integer or a decimal.)

a. Length = 13 yards and Width = 21 yards.

b. Area of rectangle = 273 square yards.

Step-by-step explanation:

Let the length of the rectangular garden be L

Let the width of the rectangular garden be W

Given the following data;

Perimeter of garden = 68 yards

Translating the word problem into an algebraic equation, we have;

W = 2L - 5 ......equation 1

Note: The formula for calculating the perimeter of a rectangle is;

68 = 2L + 2W ........equation 2

Substituting eqn 1 into eqn 2;

68 = 2L + 2(2L - 5)

68 = 2L + 4L - 10

68 = 6L - 10

6L = 68 + 10

6L = 78

L = 78/6

L = 13 yards

To find the width;

W = 2L - 5

W = 2(13) - 5

W = 26 - 5

W = 21 yards.

b. To find the area of the garden;

Area of rectangle = length * width

Area of rectangle = 13 * 21

Area of rectangle = 273 square yards.

x = 2

step-by-step explanation:

if sr parallel to ba then the sides bc and ac are in proportion, that is

= ← substitute values

= ( cross- multiply )

27x = 6(4x + 1)

27x = 24x + 6 ( subtract 24x from both sides )

3x = 6 ( divide both sides by 3 )

x = 2

two? xd

step-by-step explanation: