Two cross roads, each of width Sm, run at right angles through the centre of a rectangular park of length 70m and breadth 45m and
parallel to its sides
On the basis of the above information, answer any four of the
following questions​

Rs 57750

Step-by-step explanation:

width =5 m

length of first parallel road 70 m

area of first road 70×5=350 sq.m

length of second road 45 m

area of second road =45×5=225 sq.m

area of the common part of cross road with 5 m width that lies at the

center of the park 5×5 = 225 sq.m

area of roads = area of first road +area of second cross road−common area

=(350+225)−25

=575−25

=550sqm

​

cost of the construction per sq.m =Rs.105

total cost =550×105=Rs 57750

number one is the correct answer

step-by-step explanation: dogs and cats are mentioned, no other animals

b. would be the answer : )

step-by-step explanation:

step 1: add -16x to both sides.

16x−4y+−16x=64+−16x  

−4y=−16x+64

step 2: divide both sides by -4.

−4y /-4 = -16x + 64/-4

answer:   y=4x−16

hope i'm right