Find two integers whose sum is -9 and product is -10

4 and -12 are the integers.

Step-by-step explanation:

Therefore, x^2+8x-48=0

(x-4)(x+12)=0

Hopefully this helps you.

Please give me brainliest if it is correct.

Thanks if you do.

Step-by-step explanation:

if the two integers are x and y

xy=-10

x+y=-9

x+(-10/x)=-9

x2+9x-10=0

(x-1)(x+10)=0

x=1 or x=-10

if x=1, y=-10

if x=-10, y=1

so the two integers are 1 and -10

the answer to this is:

factor 2x2+16x+24

2x2+16x+24

=2(x+2)(x+6)

answer:

2(x+2)(x+6)

hope this hmu if needed