The letters P-R-O-B-A-B-I-L-I-T-Y are written on a set of cards. You mix the cards thoroughly. Without looking, you draw one letter then you draw another without replacing the first. Find the probability that you will select a P followed by a Y. P(P, then Y) =

P(P, then Y)=(1/11)(1/10)=1/110

Step-by-step explanation:

The number of letters in probability is 11.

There is 1 P.

The probability of drawing a P on draw 1 is the number of ways of drawing a P, which is 1, divided by the number of ways of drawing any letter, which is 11.  Thus:

Probability of drawing a P on the first draw is 1/11.

There are now 10 letters left. There is 1 Y. so

Probability of drawing a Y on the second draw given that you drew a P on the first draw is 1/10.

The probability of drawing a P on the first draw and a Y on the second draw is

(probability of a P on draw 1)(probability of drawing a Y on draw 2, given a P on draw 1)

P(P, then Y)=(1/11)(1/10)=1/110

horizontal translation of 2 units in the positive x direction

followed by

vertical translation of 3 units in the positive y direction