What are the vertices of AA'B'C'if AABC is dilated by a scale factor of 2? A(0, 10)
B(8,6)
C(4, 2)

A. A' (0,20), B' (16, 12), C'(8,4)
B. A'(0,10), B' (16,6), C'(8,2)
C. A'(0, 20), B'(8, 12). C'(4,4)
D. A'(0,5), B (4.3), C (2.1)

x=17

step-by-step explanation:

solve 3x-24=x+10

then that makes it 2x=34 because you subtract an x from both sides to get rid of the one on the right, and then you add 24 to both sides to get rid of the 24 on the left

divide by both sides by 2 to get your answer so that you can get your answer

the answer is c: divide the arc's degree measure by 360°, then multiply by the circumference of the circle.

im with everythinglos so yeahhhhh

step-by-step explanation:

38.6°

step-by-step explanation:

resultant is 10 pound

smaller force = 8 pound

angle formed = tan⁻¹(

                        =tan⁻¹(

                          =tan⁻¹(0.8)

                        =38.6°