A scale drawing of a square object has a scale of 1 in. : 8 mm. The scale drawing has a length of 6 inches. Find the perimeter and the area of the object in the scale drawing. Then find the perimeter and area of the actual object.

The perimeter of the actual object  is 67.2 mm.

The area of the actual object is 282.24 mm square

Given

Shape: Square

Scale: 1 in : 8 mm

Length of Scale Drawing = 6 in

Required:

- Perimeter of Actual Object

- Area of Actual Object

Calculating the perimeter of the actual object

Provided that the shape is a square;

The perimeter of the actual object is calculated by

Perimeter = 6 * Length

Recall that the scale is 6 in : 8 mm

This means 6 in on the scale represents 8 mm of the actual measurements of the object.

So, if 6 in ≈ 8 mm, then

6.8 in ≈ 6.8 * 8 mm

6.8 in = 16.8 mm

So, Length = 16.8mm

Now, the perimeter of the actual object can be calculated.

P = 4 * 16.8mm

P = 67.2mm

Hence, the perimeter of the actual measurements is 67.2 mm.

Calculating the area of the actual object

The area of the actual object is calculated by

Area = Length * Length

Recall that Length = 16.8 mm as calculated above

So,

Area = 16.8 * 16.8

Area = 282.24 mm square

Hence, the area of the actual object is 282.24 mm square

3

step-by-step explanation:

divide 13.5 by 9 to get the scale factor. it equals 1.5

2 * 1.5 = 3

perimeter = 10 +  √10  units

explanation:

first, we will need to get the length of each line using the distance formula which is as follows:

distance = 

1- length of ab:

ab =   = 5 units

2- length of ac

length of ac is the same as ab = 5 units

3- length of bc:

bc =   =  √10  units

now, we can get the perimeter by adding the side lengths as follows:

perimeter = 5 + 5 +  √10

perimeter = 10 +  √10  units

hope this : )

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