Sisters Amilia and Bianca play games together often. Let A represent the number of games Amilia wins monthly, and let B represent the number of games Bianca wins monthly. A and B are independent events. The mean of A is 35.7 games with a standard deviation of 5.1 games, and the mean of B is 37.3 games with a standard deviation of 6.8 games. What is the mean and standard deviation of the total number of games won, S = A + B? Mu Subscript s = 54.4 games and Sigma Subscript s= 3.4 games. Mu Subscript s = 54.4 games and Sigma Subscript s= 11.9 games. Mu Subscript s = 73.0 games and Sigma Subscript s= 8.5 games. Mu Subscript s = 73.0 games and Sigma Subscript s= 11.9 games.

expression #3 is not equivalent. the others are.

infinitely many solutions

step-by-step explanation:

we have been given the equation;

2(2x + 3) = -4 + 2(2x + 5)

we need to determine the value of x.

2(2x + 3), we expand this expression to obtain 4x + 6

similarly 2(2x + 5) will become 4x + 10

now we have;

4x + 6 = -4 + 4x + 10

4x + 6 = 4x + 10 - 4

4x + 6 = 4x + 6

the expression on the left hand side is identical to the one on the right hand side. therefore, we are looking at just a single straight line whose equation is;

y = 4x + 6

consequently, we shall have infinitely many solutions

hello!

to begin with, we're given that on earth, a rock weighs 20 pounds, and while on jupiter, that same rock weighs 42 pounds. now, we're trying to find the weight of a rock that weighs 10.5 pounds on earth, on jupiter.

to solve this, first, set up a proportion, cross-multiply, and solve it algebraically.

setting up the proportion is the hardest and the most confusing part of the problem, but it's simple.

if on earth, the rock weighs 20 lbs, and on jupiter it weighs 42 lbs, our first part of our proportion is 20/42 lbs. the second part has to be equal to each other. this means that 10.5 has to be on the numerator of the fraction, and x, the value we're trying to find, has to be on the denominator. remember that the rock weighs 10.5 lbs on earth, and we're trying to find the weight of it on jupiter (which is x).

20/42 = 10.5/x

next, you would cross-multiply.

20x = 42(10.5)

20x = 441

now, solve it algebraically by using division.

x = 22.05 lbs

this can be rounded to 22.1 lbs.

therefore, the weight of the rock on jupiter is 22.1 lbs, the fourth choice.