Triangle XYZ has vertices X(1, –1), Y(3, 4), and Z(5, –1). Nikko rotated the triangle 90° counterclockwise about the origin. What is the correct set of image points for triangle X’Y’Z’? X’(1, 1), Y’(-4, 3), Z’(1, 5)
X’(1, 1), Y’(–3, –4), Z’(–1, –5)
X’(–1, 1), Y’(–3, –4), Z’(–5, 1)
X’(–1, –1),Y’(4, –3), Z’(–1, –5)

When a figure is rotated counterclockwise about the origin, its original coordinates of point P (x,y) will now be positioned as P' (-y,x).

X (1,-1) --> X' (1,1)

Y (3,4) --> Y' (-4,3)

Z (5,-1) --> Z' (1,5)

The correct set of image points for triangle X'Y'Z' is X'(1,1), Y'(-4,3), and Z'(1,5).

Step-by-step explanation:

its (a)

Step-by-step explanation:

i hate drawn out long answers, so here. its just a.

  b.   the average rate of change of f(x) is less than the average rate of change of g(x).

step-by-step explanation:

since the length of the interval is the same in each case, we only need to compare the change in y-value to see which is greater.

so the change in y-value for function f is (6 )) = 9.

the table tells us

so the change in y-value for function g is (31 -1) = 30.

the change in y-value of f(x) on the interval is less than the change in y-value of g(x) on the same interval, so the average rate of change of f(x) is less than the average rate of change of g(x).

at home andrea has 1 2/3 kilograms of rice

step-by-step explanation: