What is the area of a square if the half of the diagonal is 6

72

Step-by-step explanation:

Cut the square into two equal triangles along the diagonal

You know that half of the diagonal is 6 so multiply that by 2 to get 12 which is the hypotenuse of your triangles

Then use the pythagorean theorem to solve for the sides

a^2 + b^2 = 12^2

a^2 + b^2 = 144

Since the original shape was a square both sides a and b are equal

a^2 = b^2

a^2 + a^2 = 144

2a^2 = 144

a^2 = 144/2

a^2 = 72

a =

Since a = b then a = =b

Multiply both sides a and b to get the area of the square

* = 72

sorry can't

step-by-step explanation:

i googled though and something came up but it was in science langueage not common english sooo

the answer for the question that you are asking is 4