Find factors of g(x)=2x^3+3x^2-23x-12 when (2x+1) is a factor

Step-by-step explanation:

STEP

1

:

Equation at the end of step 1

 (((2 • (x3)) -  3x2) -  23x) +  12

STEP  

2

:

Equation at the end of step

2

:

 ((2x3 -  3x2) -  23x) +  12

STEP

3

:

Checking for a perfect cube

3.1    2x3-3x2-23x+12  is not a perfect cube

Trying to factor by pulling out :

3.2      Factoring:  2x3-3x2-23x+12  

Thoughtfully split the expression at hand into groups, each group having two terms :

Group 1:  -23x+12  

Group 2:  2x3-3x2  

Pull out from each group separately :

Group 1:   (-23x+12) • (1) = (23x-12) • (-1)

Group 2:   (2x-3) • (x2)

Bad news !! Factoring by pulling out fails :

The groups have no common factor and can not be added up to form a multiplication.

a

step-by-step explanation:

when a number is between two straight lines it means the absolute value.

to find absolute value you need to know how many numbers is that number away from 0.

when finding absolute value the number will always come out positive

so absolute value of -3 is 3

absolute value of 3/2 is 3/2

absolute value of -2 is 2

absolute value of 3.5 is 3.5

absolute value of -1 is 1

now put these numbers in order:

a)   |-1|, |3/2|, |-2|, |-3|, |3.5|

step-by-step explanation:

circumference divided by 3.141592654 then timesthe radius twice