The diagonals of quadrilateral EFGH intersect at D(3,3). EFGCH has vertices at E(4,7) and F(-3,5). What must be the coordinates of G and H to ensure that EFGH is a parallelogram.

Step-by-step explanation:

Given

--- Diagonal

Required

Determine the coordinates of G and H

Since EFGH is a parallelogram, then:

D is the midpoint of EG and EF

For EG, we have:

Where x, y are the coordinates of G.

Multiply both sides by 2

By comparison:

==>

==>

So:

For FH, we have:

Where x, y are the coordinates of H.

Multiply both sides by 2

By comparison:

==>

==>

So:

the discriminant is 64 + 4*1*12 = 112

this is prime.

step-by-step explanation:

30

step-by-step explanation:

idk

i hope i