My question is in the image

13.2 miles

Step-by-step explanation:

To solve this, we will need to first solve for the base of the triangle and then use the information we find to solve for the shortest route.

(5.5 + 3.5)² + b² = 15²

9² + b² = 15²

81 + b² = 225

b² = 144

b = 12

Now that we know that the base is 12 miles, we can use that and the 5.5 miles in between Adamsburg and Chenoa to find the shortest route (hypotenuse).

5.5² + 12² = c²

30.25 + 144 = c²

174.25 = c²

13.2 ≈ c

Therefore, the shortest route from Chenoa to Robertsville is about 13.2 miles.

y = x + 95

y = 42 + 95

y=137 mm hg