Question 1 ( point) A 64g sample of Germanium-66 is left undisturbed for 12.5 hours. At the end of that period, only 2.0g remain. How many half-lives transpired during this time period? half-lives Answer = Blank 1:​

2.5 half-lives

Step-by-step explanation:

Find in given

is the amount after the time , `is the initial amount, is the half-life

We know that after half-life there will be twice less the initial quantity:

.

Simplifying gives

Plugging this into the initial equation, we obtain that or

Finally, just plug in the given values and find the unknown one.

From , we have that =

So you should get:

1. 3.4/4

2. 0.8/7

3. 0.5 x 3

4. 0.9 x 6

5. 10.8

6. 2.35

7. 0.567

8. 9.35

9. 0.02

10. 0.06

11. 0.16

12. 0.42

13. 0.63

14. 5.6

15. 8.1

16. 9.9

17. 0.28

18. 0.48

19. 0.27

20. 0.49

21. 0.45

22. 0.72

23. 0.9

24. 0.88

25. 0.75

26. 0.16

27. 0.328

28. 0.495

29. 0.72

30. 1.068

560

step-by-step explanation:

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