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Mathematics, 04.03.2021 18:00 drpharmd1769

How you will find out the value of 'n ' ? [ n! × 2^( n-4 ) / { 4! × ( n-4 )! } ] = [ n! × 2^( n-5 ) / { 5! × ( n-5 )! } ]


How you will find out the value of 'n ' ?

[ n! × 2^( n-4 ) / { 4! × ( n-4 )! } ] = [ n! × 2^( n-5

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How you will find out the value of 'n ' ? [ n! × 2^( n-4 ) / { 4! × ( n-4 )! } ] = [ n! × 2^( n-5 )...
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