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Mathematics, 05.03.2021 01:50 raymond5799

X, Y and Z are three mutually exclusive events. P(X) = 0.4, P(Y) = 0.3 and P(
XU Z) = 0.6.
Find:
() P(XUY)
(i) P(Z)
(ii) The probability that none of X, Y or Z
happens

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Answers: 2

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You know the right answer?
X, Y and Z are three mutually exclusive events. P(X) = 0.4, P(Y) = 0.3 and P(
XU Z) = 0.6.
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