Kayson is looking at two buildings, building A and building B, at an angle of elevation of 40°. Building A is 120 feet away, and building B is 60 feet away. Which building is taller and by approximately how many feet? Building A; it is around 100.69 feet taller than building B
Building A; it is around 50.34 feet taller than building B
Building B; it is around 100.69 feet taller than building A
Building B; it is around 50.34 feet taller than building A

B. Building A; it is around 50.34 feet taller than building B.

Step-by-step explanation:

Let the height of building A be represented by x, and that of B by y. Applying the required trigonometric function, we have;

Tan θ =

Tan 40 =

x = 120 x Tan 40

  = 120 x 0.8391

x = 100.692

Thus, the height of building A is 100.69 feet.

The height of building B can be determined by;

Tan θ =

Tan 40 =

y = 60 x Tan 40

  = 60 x 0.8391

y = 50.346

Thus, the height of building B is 50.35 feet.

Therefore it can be observed that Building A is about 50.34 feet taller than building B.

step-by-step explanation: