PLEASE HELP ME: The runway on an aircraft carrier is less than 350 feet long (most fighter type aircraft need 2,300 feet to take off and slightly more to stop after landing). In order to stop a jet in so little space, arresting cables (a. k.a. "the wire") are stretched out on the deck of the ship to catch a special hook on the plane. These cables pull the jets to a stop extremely fast to prevent them from falling into the ocean. You are the pilot of a F/A18 "Hornet" jet trying to land on the carrier. You are 5000 feet from the wire" and still 300 feet above the ship's deck. Your task: Determine the appropriate angle of elevation from the ship to you that would be necessary for you to catch the wire and land safely on the ship. How far are you from the wire? What would happen if your angle was too big or too small?​

THANK YOU!! :

i need help with that one too

(x3 + 6x2 + 2x - 6) • (x - 1)

step-by-step explanation:

polynomial long division :

3.2     polynomial long division

dividing :   x4+5x3-4x2-8x+6

                              ("dividend")

by         :     x-1     ("divisor")

dividend     x4   +   5x3   -   4x2   -   8x   +   6

- divisor   * x3     x4   -   x3            

remainder         6x3   -   4x2   -   8x   +   6

- divisor   * 6x2         6x3   -   6x2        

remainder             2x2   -   8x   +   6

- divisor   * 2x1             2x2   -   2x    

remainder               -   6x   +   6

- divisor   * -6x0               -   6x   +   6

remainder                     0

quotient :   x3+6x2+2x-6   remainder:   0

the formula of a slope:

from a table we have

substitute:

the slope of f(x) is -1.

the graph of funcfion g(x) is a horizontal line. the slope of a horizontal line is equal 0. therefore the slope of g(x) is 0.

-1 < 0