A plane take off from the Indianapolis airport and ascends for a distance of 3,192 feet. If the plane is currently flying
at an altitude of 1,078 feet, what was the plane's angle of
elevation at takeoff?

step-by-step explanation:

16.80 times .20= 3.36

step-by-step explanation:

i would be 2,000 just get the square root of 50 which is 2500 and the divid 4/5 and last thing multiply the answer you get for that by the square root of 50

step-by-step explanation:

yx = 36

step-by-step explanation:

cos f = opposite side/ hypotenuse

cos f = yw / yx

we know cos f = 4/9 and yw =16

4/9 = 16/yx

multiply each side by yx

4/9 yx = 16/ yx * yx

4/9 yx = 16

multiply each side by 9/4

9/4 * 4/9 yx = 16 *9/4

yx = 36