A mother spins her son in a circle of radius RRR at angular speed \omega_iω i
​
omega, start subscript, i, end subscript. Then the mother pulls in her arms and spins him in a circle of radius \dfrac{1}{2}R
2
1
​
Rstart fraction, 1, divided by, 2, end fraction, R with the same angular speed.
How does the magnitude of the child's centripetal acceleration change when the mother pulls her arms in?

answer: median

step-by-step explanation:

the median is the middle value when a data set is ordered from least to greatest

the answer to this is:

factor 2x2+16x+24

2x2+16x+24

=2(x+2)(x+6)

answer:

2(x+2)(x+6)

hope this hmu if needed

secant-secant formula:

(whole secant) x (external part) =           (whole secant) x (external part)

(8+y-2) *8=                                           (y+4+6) *6

(y+6)*8 = (y+10) *6

distribute

8y+48 = 6y +60

subtract 6y from each side

2y +48 = 60

subtract 48 from each side

2y = 12

divide by 2

y = 6

sv =     (y+4+6)

sv   = 6+4+6

sv = 16