If f(x)=x^3-8x^2+9x+18 and f(3)=0 ; If f(3)=0, then find all of the zeros of f(x) algebraically

(1,4) is on graph of f(x)

f(1) = 4

so 1/4 f(x)

1/4 f(1)

1/4. ×4

1

so point for function 1/4. f(x) is (1,1)

the discriminant is 64 + 4*1*12 = 112

this is prime.

step-by-step explanation:

1 x=22.52

2: 65/39=604+39x

65x-39x=604

26x=604

x=604/26

×=23.23