Find the slope of the line that passes through A(0,−5) and B(3,−4)

1/3

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(-4-(-5))/(3-0)

m=(-4+5)/3

m=1/3

given that triangle abc is transformed two times to get triangle

a"b"c"

first abc is transformed in to a'b'c' as follows:

the coordinates of a are (1,-1) and transformed into a'(-1,1)

similarly b (4,-2) became b'(-4,2) and

c(7,-2) became c'(-7,2)

i.e. (x,y) becomes (-x,-y)

this is nothing but reflection about a point here origin.

thus first transformation is reflection on the origin.

next is exactly shifting 3 units down

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