3(2x+d)+c(x+5)=10x+17 find c and d

c = 4, d = - 1

Step-by-step explanation:

Expand and simplify left side, then compare coefficients of like terms on the right side, that is

3(2x + d) + c(x + 5) ← distribute parenthesis

6x + 3d + cx + 5c

= x(6 + c) + 3d + 5c

Compare terms with those on the right side

coefficients of x- terms

6 + c = 10 ( subtract 6 from both sides )

c = 4

constant terms

3d + 5c = 17, that is

3d + 5(4) = 17

3d + 20 = 17 ( subtract 20 from both sides )

3d = - 3 ( divide both sides by 3 )

d = - 1

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