A spinner marked A, B, C is spun then a 6-sided die is rolled. What is the probability of getting a B and then a 6. 131 third

161 sixth

1121 over 12

118

Given:

A spinner marked A, B, C is spun then a 6-sided die is rolled.

To find:

The probability of getting a B and then a 6.

Solution:

We know that,

Total possible values for a spinner are 3. So, the probability of getting B, we get

Total possible values for a die are 6. So, the probability of getting 6, we get

Now, the probability of getting a B and then a 6 is

The required probability is .

Therefore, the correct option is D.

step-by-step explanation:

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step-by-step explanation:

y = | -2(-2) |     →     y = | 4 |     →     y = 4       ⇒   (-2, 4)

y = | -2(-1) |     →     y = | 2 |     →       y =   2       ⇒   (-1, 2)    

y = | -2(0) |     →     y = | 0 |     →       y = 0         ⇒   (0, 0)

y = | -2(1) |   c →     y = | -2 |     →     y =   2         ⇒   (1, 2)    

y = | -2(2) |     →     y = | - 4 |     →     y =   4         ⇒   (2, 4)