A sandwich shop offers 3 different kinds of bread, 4 different kinds of meat, and 6 different toppings. How many different sandwiches with one bread, one meat, and one topping are possible?​

yeah

Step-by-step explanation:

0

Your second impression was "right"; the answer is 36 in one restricted interpretation of the problem, in which a sandwich has precisely one type of bread, one type of meat, and one type of cheese.

The largest possible interpretation is that a sandwich consists of a top bread, 1 to 3 types of meat, 1 to 3 types of cheese, and a bottom bread which could be different from the top slice of bread (but two sandwiches are considered the same if the only difference is turning one upside down). The answer to that problem involves, for example, seven possible combination of meats, and is

(42)bread⋅(23−1)meat⋅(23−1)cheese=6⋅7⋅7=594

If you must use the same type of bread top and bottom the answer is

(41)bread⋅(23−1)meat⋅(23−1)cheese=4⋅7⋅7=396

the answer is:

the correct option:

b.

to solve the problem, we need to remember how to operate to simplify exponential expressions using the logarithms.

we are given the equation:

then, using placing logarith with base 7 on both sides of the equation, we have:

so, rounding the obtained result to two decimal places (nearest hundreth), we have:

hence, we have that the correct option:

b.

have a nice day!