There are seven nickels and seven dimes in your pocket. You randomly pick a coin out of your pocket and place it on a counter.

3/13

Step-by-step explanation:

Here is the full question

There are seven nickels and seven dimes in your pocket. You randomly pick a coin out of your pocket and place it on a counter. Then you randomly pick another coin. Find the probability that both coins are nickels.

Because there is no replacement, after you pick the first coin, the number of coins in your pocket becomes 13 and the number of nickels in your pocket becomes 6

probability that both coins are nickels = probability that the first coin is a nickel x probability second coin is a nickel

7/14 x 6/13 = 3/13

the answer   is 200

step-by-step explanation:

this is a problem about poisson probabilities.   i don't know if you've

already studied poisson distributions, or if you have a place to look

to read more about the subject.  

here's how you can see a poisson distribution coming.   when there are

a lot of events that may happen at any time (or any place), and when

you're counting how many of them happen at a particular time (or a

particular place), and each event is independent of the others, then

the result is a poisson distribution.   this is roughly true for the

chocolate chips; one chip being in a cookie has only a small effect on

the probability that another chip will be in the cookie.

once you know you have a poisson distribution, you know a lot.   there

is only one parameter to a poisson distribution, so if you know the

mean, you know everything.   the form of the distribution is

  probability of n chips = {[e^(-x)]*(x^n)} / (n! )

d

step-by-step explanation:

given

y + 3 = - 4(x - 2) ← distribute the parenthesis

y + 3 = - 4x + 8 ( subtract 3 from both sides )

y = - 4x + 5 → d