The parallelograms have a combined area of 3 1/7 square yards. The height of each parallelogram is 1 2/7 yards. How long is the base of each parallelogram? What is the area of the smallest rectangle of wall that the mirror could fit on?

a) How long is the base of each parallelogram?

1 2/9 yards.

b) What is the area of the smallest rectangle of wall that the mirror could fit on?

3 Square yards

Step-by-step explanation:

The parallelograms have a combined area of 3 1/7 square yards. The height of each parallelogram is 1 2/7 yards.

Step 1

We find the area of each of the parallelogram

This is calculated as:

Combined area of the parallelograms ÷ 2

= 3 1/7 square yards ÷ 2

= 22/7 square yards ÷ 2

= 22/7 square yards × 1/2

= 11/7 square yards

= 1 4/7 square yards.

Step 2

How long is the base of each parallelogram?

The height of each parallelogram is 1 2/7 yards.

Area of parallelogram = Base × Height

Base of each parallelogram = Area of each parallelogram/Height of each parallelogram

= 1 4/7 square yards ÷ 1 2/7 yards

= 11/7 square yards ÷ 9/7 yards

= 11/7 square yards × 7/9 yards

= 11/9 yards

= 1 2/9 yards.

Step 3

What is the area of the smallest rectangle of wall that the mirror could fit on?

Area of a rectangle = Length × Width

Length =(Base of parallelogram × 2)

Width = Base of parallelogram = 1 2/9 yards = 11/9 yards

Length = 1 2/9 yards × 2

= 11/9 × 2 = 22/9 yards

Area of rectangle = 11/9 × 22/9

= 242/81 square yards

= 2.987654321 square yards

Approximately = 3 Square yards

the answer is the option b

the range is all real numbers

step-by-step explanation:

we know that

the absolute value parent function is equal to

see the attached figure to better understand the problem

so

a. it is v-shaped > is true

b. the range is all real numbers > is not true

because the range is the > [0,∞)

all real numbers greater than or equal to zero

c. it goes through the origin > is true

d. the domain is all real numbers > is true

step-by-step explanation: