Write the equation of the line in slope-intercept form using y=mx+b​

The slope is given as m = 7m=7 and the yy-intercept as b = - \,4b=−4. Substituting into the slope-intercept formula y = mx + by=mx+b, we have

since m=7 and b=-4, we can substitute that into the slope-intercept form of a line to get y=mx+b → y=7x-4

The slope is positive thus the line is increasing or rising from left to right, but passing through the yy-axis at point \left( {0, - \,4} \right)(0,−4).

Step-by-step explanation:

hello from mrbilldoesmath!

answer:   (7x + 6y) ( 49x^2 - 42xy + 36y^2)

discussion:

in general, the factorization of a^3 + b^3 is

a^3 + b^ 3 = (a + b) ( a^2 - ab + b^2)

in our case note that 343 = 7^3 and 216 = 6^3 so the equation becomes:

343x^3 + 216y^3 = (7x)^3 + (6y)^3

if you think of a (above) as 7x and b as 6y the factorization becomes

343x^3 + 216y^3 =

((7x + 6y) (   (7x)^2 - 7x*6y + (6y)^2)   =

(7x + 6y) ( 49x^2 - 42xy + 36y^2)

you,

mrb

(a + b) (a^2 - a b + b^2)