A bag contains 10 marbles: 2 are green, 2 are red, and 6 are blue. Keith chooses a marble at random, and without putting it back, chooses another one at random. What is the probability that the first marble is green and the second is red? Write your answer as a fraction in simplest form.

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Step-by-step explanation:

The probability  that both marbles she chooses are blue is 2/15

Given : A bag contains 10 marbles: 4 are green, 2 are red, and 4 are blue. Christine chooses a marble at random, and without putting it back, chooses another one at random.

To find : What is the probability that both marbles she chooses are blue?

Solution :

Total number of marbles = 10

Green marbles = 4

Red marbles = 2

Blue marbles = 4

Probability is favorable outcome upon total number of outcomes.

Probability of getting first marble is blue.

P (first  blue marble) = 4/10 = 2/5

Without replacement,

i.e. Blue marble left = 3

Total marble left = 9

Probability of getting second marble is blue.

P (second  blue marble) = 3/9 =1/3

The probability that both marbles she chooses are blue is

P (both blue marbles) = 2/5 x 1/3

P (both blue marbles) = 2/15

use the power rule  

( a b ) n = a n b n

to distribute the exponent.

apply the product rule to  

3 x 2 y 3 . ( 3 x 2 ) 2 ( y 3 ) 2

apply the product rule to  

3 x 2 . 3 2 ( x 2 ) 2 ( y 3 ) 2

raise  

3

to the power of  

2 . 9 ( x 2 ) 2 ( y 3 ) 2 multiply the exponents in   ( x 2 ) 2

.

apply the power rule and multiply exponents,  

( a m ) n = a m n . 9 x 2 ⋅ 2 ( y 3 ) 2

multiply  

2   by   2 . 9 x 4 ( y 3 ) 2

multiply the exponents in  

( y 3 ) 2 .

apply the power rule and multiply exponents,  

( a m ) n = a m n . 9 x 4 y 3

⋅

2

multiply  

3   by   2 . 9 x 4 y 6

step-by-step explanation:

b) 1/3 * 1/5

step-by-step explanation:

each smallest part is 1/15 since the written one is 1/5 and it's divided by 3 equal parts. (1/5 )/3 = 1/15 = 1/3 * 1/5