Jesse and Benjamin are asked to factor 100x^2−100. Here are their solutions. Who is correct? Jesse
100x^2−100=(10x)^2−10^2
=(10x-10)(10x+10)
=10(x-1)(10)(x+1)
=100(x-1)(x+1)

Benjamin
100x^2-100=100(x^2-1)
=100(x-1)(x+1)