Look at the right triangle ABC below: B
A
A student made the following chart to prove that AB2 + BC2 = AC2:
Statement
Justification
1. Triangle ABC is similar to triangle BDC
1. Angle ABC = Angle BDC and Angle BCA = Angle DCB
2. BC2 = AC x DC
2. BC ÷ DC = AC ÷ BC because triangle ABC is similar to S
triangle BDC
is 3. Triangle ABC is similar to triangle ADB
3. Angle ABC Angle BAD and Angle BAC = Angle ABD
4. AB2 = AC x AD
4. AB ÷ AD = AC ; AB because triangle ABC is similar to
triangle ABD
5 AB2
BC2 = AC x AD + AC X DC = AC
(AD + DC)
5. Adding Statement 2 and Statement 4
6. AB2 + BC2 = AC2
6. AD + DC = AC
What is the flaw in the student's proof? (1 point)

eve and marks ratios are equivalent

step-by-step explanation:

answer: integers are just whole numbers: positive, negative, and zero.

i = {-∞, -2, -1, 0, 1, 2, 3, ∞}

let x = 1st integer

let y = 2nd integer

x = 3y + 17   {equation 1}

xy = -24         {equation 2}

substitute 3y+17 in place of x n equation 2

and solve for y.

(3y+17)y = -24

3y2 + 17y = -24

3y2 + 17y + 24 = 0

from quadratic equation:

y = [-17±√(172-4(3)(24))]/(2(3))

y = (-17 ±√1)/6

y = (-17+1)/6   or     y = (-17-1)/6

y = -16/6           or     y = -18/6

y = -2 2/3         or   y = -3

since we are dealing with

y = -3

x = 3y+17 = -9+17 = 8

the integers are -3, 8

step-by-step explanation:

most likely linear (proportionate)

step-by-step explanation:

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