In a survey of 200 families, the number that read recent issues of a certain monthly
Journal were found to be - March only 36,
March but not April 46; March and
16 March Sai May 96: May and April
16. none of the 3 months 48. By means
of Venn diagram
or otherwise determine
is the number of families that read April issue
2) the number of families that read two
Consecutive issues?
3) the number of families that read the May
issue, if and only if they did not read
April issue?
4)the number of families that read March
and April issues but not the May issue​

a

step-by-step explanation:

u take $30 minus $24. the answer/original($30)

table 3 represents a direct variation function. : )

85.560%

step-by-step explanation:

conditional probability is defined as:

p(a|b) = p(a∩b) / p(b)

in other words, the probability that a occurs, given that b has occurred = the probability that both a and b occur / the probability that b occurs.

in this example:

p(turns 64 | turns 44) = p(turns 64 & turns 44) / p(turns 44).

if someone turns 64, they must have already turned 44, so:

p(turns 64 | turns 44) = p(turns 64) / p(turns 44)

on page 42, we see that of the original 100,000, 94944 turn 44, and 81234 turn 64.   therefore:

p(turns 64 | turns 44) = 81234 / 94944

p(turns 64 | turns 44) = 0.85560

a) 0

step-by-step explanation:

i^413 x i^0 = 0 as any number multiplied by a zero is

happy to

pls mark as brainliest.