I need a little help with this geometry

Both ABC and DEF are right triangles.

Because BC is congruent to EF, two of the corresponding angles of the triangle are congruent.

C is congruent to F

(I don't know the last one, In sorry, I hope this helps-)

30005

yes ok                                            

option (b) is correct

step-by-step explanation:

to find the solution of this system, we need to convert it into reduced row-echelon form. we have,

after applying row operations r2 -> r2/2 and r3 -> r3/3, we get,