“A cylindrical bale of hay needs to be wrapped in plastic. It has a height of 9 ft. and a radius that is one-third of its height. How many square feet of plastic is needed?”

A = 226.08

Step-by-step explanation:

Assuming that you are  wrapping the sides of the cylinder and the circular top and bottom, then the formula for the surface area of the cylinder is:

A=2πrh+2πr^2 so substitute for each variable A=2(3.14)(3)(9) + 2(3.14)(3)^2

notice how I substituted 3 for the radius since it is 1/3 of 9 (the height)

Solving we get A = 169.56 + 56.52 = 226.08