What is the slope of the line that passes through the points (6, -10)and (3, -13)?Write your answer in simplest form.

y = x - 16

Step-by-step explanation:

(6, -10) & (3, -13)

First you want to find the slope of the line that passes through these points. To find the slope of the line, we use the slope formula: (y₂ - y₁) / (x₂ - x₁)

Plug in these values:

(-13 - (-10)) / (3 - 6)

Simplify the parentheses.

= (-13 + 10) / (-3)

= (-3) / (-3)

Simplify the fraction.

=-3/-3

= 1

This is your slope. Plug this value into the standard slope-intercept equation of y = mx + b.

y = 1x + b

or

y = x + b

To find b, we want to plug in a value that we know is on this line: in this case, I will use the second point (3, -13). Plug in the x and y values into the x and y of the standard equation.

-13 = 1(3) + b

To find b, multiply the slope and the input of x(3)

-13 = 3 + b

Now, subtract 3 from both sides to isolate b.

-16 = b

Plug this into your standard equation.

y = x - 16

This is your equation.

Check this by plugging in the other point you have not checked yet (6, -10).

y = x - 16

-10 = (6) - 16

-10 = 6 - 16

-10 = -10

Your equation is correct.

Hope this helps!

d

step-by-step explanation:

d

there are no figures how am i supposed to answer this question

step-by-step explanation: