The width of the rectangle is one-fourth of its length.
If the perimeter is 40 cm,
find the dimensions of the
rectangle.
4w = L
2L + 2w = 40

84cm^2

Step-by-step explanation:

P=2l+2w

We are given,

P=40cm

l=2w+2

Plug these into the first formula and solve for the dimensions,

length and width, of the rectangle:

40=2(2w+2)+2w              Simplify

40=4w+4+2w

40=6w+4

36=6w

6=w OR the width is 6cm, therefore,

the length is

l=2(6)+2

l=14cm

To calculate the area of a rectangle, A=lw,

plug the length,14cm, and the width, 6cm, into this formula

A=(14)(6)

A=84cm2 OR the area of the rectangle is 84cm^2

step-by-step explanation:

when the line is solid:

when the line is dashed:

this > inequality sign means:

this < inequality sign means:

this > inequality sign means:

this < inequality sign means:

about the problem:

srry i'm not done ! i'll

answer: 7

step-by-step explanation: