AABC is an isosceles triangle in which AB= AC, CP =AB and BQ= AC. Prove that ∆CPA is congruent∆BOA.​

constant acceleration- a

constant velocity- c

no velocity or acceleration- b

explanation:

for body moving with a constant acceleration, the rate of change of displacement changes over time. this is proven by the increasing gradient of the curve (a) against time.

a body that is moving at constant velocity covers equal distances over equal periods of time, thus the straight line with a constant gradient c.

a stationary body   covers no displacement as time elapses. thus the flat line with   zero gradient.

i found two solutions,   n = 2 • ± √3 = ± 3.4641

step-by-step explanation: