For parallelogram PQRS, PT=2x-1, QT=x+4RT = y 1, and ST - 3y - 11. Find the values of x and y: Note: You must be able to solve a systems of equations for this
problem
L2x-1
X+4
y-1
Зу-11
S.
R.

area = length x width

length = 2 x width

32 = 2 x width x width

32 = 2 x width^2

36 = width ^2  

width = 6

length = 12

area is 32

perimeter = 2 x 12 + 2 x 6 = 24 + 12 = 36

step-by-step explanation:

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i think is g(1)=-1.

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answer

false

explanation

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